Course Content
Module 1: Introduction to Electrochemistry
Overview of electrochemistry, its applications, and relevance in daily life and industrial processes.
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Module 2: Redox Reactions
Understanding oxidation, reduction, oxidation numbers, and balancing redox equations.
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📘 Module 7: Conductivity of Electrolyte Solutions
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📘 Module 9: Applications of Electrolysis in Industry
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📘 Module 10: Redox Titrations and Calculations
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Advanced Chemistry: Electrochemistry

Introduction
This titration involves the reaction between acidified potassium permanganate (KMnO₄) and iron(II) ions (Fe²⁺). It is a standard redox titration in NECTA Chemistry practicals and is used to determine the concentration of Fe²⁺ in a solution.


🔹 Reaction Principle

KMnO₄ acts as a strong oxidizing agent in acidic medium and oxidizes Fe²⁺ to Fe³⁺. KMnO₄ is self-indicating due to its purple color, which fades upon reduction.

Balanced Ionic Equation:

mathematica
MnO₄⁻ + 5Fe²⁺ + 8H⁺ → Mn²⁺ + 5Fe³⁺ + 4HO

🔹 Theory

  • KMnO₄ is purple; reduced to Mn²⁺ (colorless/pale pink)

  • Fe²⁺ is oxidized to Fe³⁺ (colorless in dilute acid)

  • H₂SO₄ is used to acidify the solution (not HCl, to avoid interference)

  • The endpoint is a faint pink color persisting after the final drop


🔹 Apparatus and Chemicals

  • Burette, pipette, conical flask, white tile

  • KMnO₄ solution (in burette)

  • FeSO₄ or Fe²⁺ solution (in flask)

  • Dilute H₂SO₄ (for acidification)


🔹 Procedure

  1. Rinse burette with KMnO₄, fill, and record initial volume

  2. Pipette 25.00 mL of Fe²⁺ solution into a conical flask

  3. Add ~10 mL of dilute H₂SO₄ to acidify the solution

  4. Titrate by adding KMnO₄ slowly with constant swirling

  5. Stop when the pale pink color persists for 30 seconds

  6. Record final burette reading and calculate volume used

  7. Repeat until concordant results are obtained (within ±0.10 mL)


🧠 Calculation Example

Given:

  • 25.00 mL of Fe²⁺ is titrated

  • Average volume of 0.0200 M KMnO₄ used = 22.60 mL

Balanced equation mole ratio:
1 MnO₄⁻ : 5 Fe²⁺

Step 1: Calculate moles of KMnO₄ used

ini
Moles = M × V(L) = 0.0200 × 0.0226 = 4.52 × 10⁻⁴ mol

Step 2: Moles of Fe²⁺ (from mole ratio)

 
Fe²⁺ = 5 × 4.52 × 10⁻⁴ = 2.26 × 10⁻³ mol

Step 3: Concentration of Fe²⁺

ini
C = n / V = 2.26 × 10⁻³ mol / 0.025 L = 0.0904 M

Answer: Concentration of Fe²⁺ = 0.0904 mol/dm³


🔹 Observations and Color Change

  • Before endpoint: Solution is colorless (Fe²⁺ only)

  • Endpoint: First permanent pale pink color

  • After endpoint: Pale pink becomes darker if KMnO₄ is in excess


✅ Summary

  • KMnO₄ oxidizes Fe²⁺ in acidic solution

  • Reaction ratio is 1:5 (MnO₄⁻ : Fe²⁺)

  • KMnO₄ is self-indicating

  • Use only H₂SO₄ for acidification

  • Observe and record results to 2 decimal places for NECTA